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53. Maximum Subarray share

Problem Statement

Given an integer array nums, find the subarray with the largest sum, and return its sum.

 

Example 1:

Input: nums = [-2,1,-3,4,-1,2,1,-5,4]
Output: 6
Explanation: The subarray [4,-1,2,1] has the largest sum 6.

Example 2:

Input: nums = [1]
Output: 1
Explanation: The subarray [1] has the largest sum 1.

Example 3:

Input: nums = [5,4,-1,7,8]
Output: 23
Explanation: The subarray [5,4,-1,7,8] has the largest sum 23.

 

Constraints:

  • 1 <= nums.length <= 105
  • -104 <= nums[i] <= 104

 

Follow up: If you have figured out the O(n) solution, try coding another solution using the divide and conquer approach, which is more subtle.

Solution:

go
package main

import "math"

func maxSubArray(nums []int) int {
	currSum, maxSum := 0, math.MinInt

	for _, num := range nums {
		currSum += num
		maxSum = int(math.Max(float64(maxSum), float64(currSum)))
		if currSum < 0 {
			currSum = 0
		}
	}

	return maxSum
}

...


Released under the MIT License.