412. Fizz Buzz

Problem Statement

Given an integer n, return a string array answer (1-indexed) where:

answer[i] == "FizzBuzz" if i is divisible by 3 and 5.
answer[i] == "Fizz" if i is divisible by 3.
answer[i] == "Buzz" if i is divisible by 5.
answer[i] == i (as a string) if none of the above conditions are true.

Example 1:

Input: n = 3
Output: ["1","2","Fizz"]

Example 2:

Input: n = 5
Output: ["1","2","Fizz","4","Buzz"]

Example 3:

Input: n = 15
Output: ["1","2","Fizz","4","Buzz","Fizz","7","8","Fizz","Buzz","11","Fizz","13","14","FizzBuzz"]

Constraints:

1 <= n <= 10⁴

Solution:

Rust

impl Solution {
    pub fn fizz_buzz(n: i32) -> Vec<String> {
        let mut res = Vec::new();

        for i in 1..=n {
            // same as divisible by 3 and 5
            if i % 15 == 0 {
                res.push("FizzBuzz".to_string());
            } else if i % 3 == 0 {
                res.push("Fizz".to_string());
            } else if i % 5 == 0 {
                res.push("Buzz".to_string());
            } else {
                res.push(i.to_string());
            }
        }

        res
    }
}

412. Fizz Buzz #

Problem Statement #

Solution: #

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412. Fizz Buzz

Problem Statement

Solution:

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