English
1108. Defanging an IP Address
Problem Statement
Given a valid (IPv4) IP address
, return a defanged version of that IP address.
A defanged IP address replaces every period "."
with "[.]"
.
Example 1:
Input: address = "1.1.1.1"
Output: "1[.]1[.]1[.]1"
Example 2:
Input: address = "255.100.50.0"
Output: "255[.]100[.]50[.]0"
Constraints:
- The given
address
is a valid IPv4 address.
Solution:
rs
impl Solution {
pub fn defang_i_paddr(address: String) -> String {
let mut result = String::default();
for c in address.chars() {
if c == '.' {
result.push_str("[.]");
} else {
result.push(c);
}
}
result
}
}
...