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1108. Defanging an IP Address share

Problem Statement

Given a valid (IPv4) IP address, return a defanged version of that IP address.

A defanged IP address replaces every period "." with "[.]".

 

Example 1:

Input: address = "1.1.1.1"
Output: "1[.]1[.]1[.]1"

Example 2:

Input: address = "255.100.50.0"
Output: "255[.]100[.]50[.]0"

 

Constraints:

  • The given address is a valid IPv4 address.

Solution:

rs
impl Solution {
    pub fn defang_i_paddr(address: String) -> String {
        let mut result = String::default();

        for c in address.chars() {
            if c == '.' {
                result.push_str("[.]");
            } else {
                result.push(c);
            }
        }

        result
    }
}

...


Released under the MIT License.