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112. Path Sum share

Problem Statement

Given the root of a binary tree and an integer targetSum, return true if the tree has a root-to-leaf path such that adding up all the values along the path equals targetSum.

A leaf is a node with no children.

 

Example 1:

Input: root = [5,4,8,11,null,13,4,7,2,null,null,null,1], targetSum = 22
Output: true
Explanation: The root-to-leaf path with the target sum is shown.

Example 2:

Input: root = [1,2,3], targetSum = 5
Output: false
Explanation: There two root-to-leaf paths in the tree:
(1 --> 2): The sum is 3.
(1 --> 3): The sum is 4.
There is no root-to-leaf path with sum = 5.

Example 3:

Input: root = [], targetSum = 0
Output: false
Explanation: Since the tree is empty, there are no root-to-leaf paths.

 

Constraints:

  • The number of nodes in the tree is in the range [0, 5000].
  • -1000 <= Node.val <= 1000
  • -1000 <= targetSum <= 1000

Solution:

go
package main

// Definition for a binary tree node.
type TreeNode struct {
	Val   int
	Left  *TreeNode
	Right *TreeNode
}

func hasPathSum(root *TreeNode, targetSum int) bool {
	return dfs(root, targetSum, 0)
}

func dfs(node *TreeNode, targetSum int, sum int) bool {
	if node == nil {
		return false
	}

	sum += node.Val

	if node.Left == nil && node.Right == nil {
		return sum == targetSum
	}

	return dfs(node.Left, targetSum, sum) || dfs(node.Right, targetSum, sum)
}

...


Released under the MIT License.