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1672. Richest Customer Wealth
Problem Statement
You are given an m x n
integer grid accounts
where accounts[i][j]
is the amount of money the iβββββββββββthββββ
customer has in the jβββββββββββth
ββββ bank. Return the wealth that the richest customer has.
A customer's wealth is the amount of money they have in all their bank accounts. The richest customer is the customer that has the maximum wealth.
Β
Example 1:
Input: accounts = [[1,2,3],[3,2,1]]
Output: 6
Explanation:
1st customer has wealth = 1 + 2 + 3 = 6
2nd customer has wealth = 3 + 2 + 1 = 6
Both customers are considered the richest with a wealth of 6 each, so return 6.
Example 2:
Input: accounts = [[1,5],[7,3],[3,5]]
Output: 10
Explanation:
1st customer has wealth = 6
2nd customer has wealth = 10
3rd customer has wealth = 8
The 2nd customer is the richest with a wealth of 10.```
<p><strong class="example">Example 3:</strong></p>
Input: accounts = [[2,8,7],[7,1,3],[1,9,5]] Output: 17
<p>Β </p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>m ==Β accounts.length</code></li>
<li><code>n ==Β accounts[i].length</code></li>
<li><code>1 <= m, n <= 50</code></li>
<li><code>1 <= accounts[i][j] <= 100</code></li>
</ul>
::: details _Click to open Hints_
- Calculate the wealth of each customer
- Find the maximum element in array.
:::
## Solution:
::: code-group
```rs [Rust]
impl Solution {
pub fn maximum_wealth(accounts: Vec<Vec<i32>>) -> i32 {
let mut max = 0;
for account in accounts {
let mut sum = 0;
for money in account {
sum += money;
}
if sum > max {
max = sum;
}
}
max
}
}
:::
...