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349. Intersection of Two Arrays share

Problem Statement

Given two integer arrays nums1 and nums2, return an array of their intersection. Each element in the result must be unique and you may return the result in any order.

 

Example 1:

Input: nums1 = [1,2,2,1], nums2 = [2,2]
Output: [2]

Example 2:

Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4]
Output: [9,4]
Explanation: [4,9] is also accepted.

 

Constraints:

  • 1 <= nums1.length, nums2.length <= 1000
  • 0 <= nums1[i], nums2[i] <= 1000

Solution:

rs
impl Solution {
    pub fn intersection(nums1: Vec<i32>, nums2: Vec<i32>) -> Vec<i32> {
        let (mut nums1, mut nums2) = (nums1, nums2);
        let mut res = Vec::new();
        let (mut i, mut j) = (0, 0);

        nums1.sort();
        nums2.sort();

        while i <= nums1.len() - 1 && j <= nums2.len() - 1 {
            if nums1[i] == nums2[j] {
                if res.is_empty() || res[res.len() - 1] != nums1[i] {
                    res.push(nums1[i]);
                }
                i += 1;
                j += 1;
            } else if nums1[i] < nums2[j] {
                i += 1;
            } else {
                j += 1;
            }
        }

        res
    }
}

...


Released under the MIT License.